RedRagToAnOrc
09-21-2005, 12:09 PM
Among some of my scarier musings during Maths lessons is this one;
A parody of the 'Ten green bottles' classic.
Now you may laugh, you may scream. But, I think we should create a never ending poem out of this. Purely for fun. I've done the first three verses and I'd like you to continue in the same sort of format. I'll update the original post as required.
As it stands;
Ten green bottles, standing on the wall,
Ten green bottles, standing on the wall,
And if x green bottles, should accidentally fall,
There'd be ten-minus-x green bottles, standing on the wall.
Ten-minus-x green bottles, standing on the wall,
Ten-minus-x green bottles, standing on the wall,
And if z green bottles, should accidentally fall,
There'd be ten-minus-open-brackets-x-plus-y-close-brackets green bottles, standing on the wall.
Ten-minus-open-brackets-x-plus-y-close-brackets green bottles, standing on the wall,
Ten-minus-open-brackets-x-plus-y-close-brackets green bottles, standing on the wall,
And if you wish to find the combined circumferences of those bottles, standing on the wall,
It's ten-minus-open-brackets-x-plus-y-close-brackets-multiplied-by-two-pi-times-the-radius-in-cm-squared circular tops of green bottles, standing on the wall.
Ten-minus-open-brackets-x-plus-y-close-brackets-multiplied-by-two-pi-times-the-radius-in-cm-squared circular tops of green bottles standing on the wall.
Ten-minus-open-brackets-x-plus-y-close-brackets-multiplied-by-two-pi-times-the-radius-in-cm-squared circular tops of green bottles standing on the wall.
And if you want to differentiate the combine circumfrences of those bottles with respect to the radius of said bottles.
You get Ten-minus-open-breacket-x-plus-y-close-bracket-times-two-pi-whoops, the bottles got lost in the differentiation.
Ten-minus-open-bracket-x-plus-y-close-bracket-times-two-pi green bottles standing on the wall
Ten-minus-open-bracket-x-plus-y-close-bracket-times-two-pi green bottles standing on the wall
If you want the reflexive property of said equation
You get Ten-minus-open-bracket-x-plus-y-close-bracket-times-two-pi equals Ten-minus-open-bracket-x-plus-y-close-bracket-times-two-pi green bottles on the wall.
Please continue!
A parody of the 'Ten green bottles' classic.
Now you may laugh, you may scream. But, I think we should create a never ending poem out of this. Purely for fun. I've done the first three verses and I'd like you to continue in the same sort of format. I'll update the original post as required.
As it stands;
Ten green bottles, standing on the wall,
Ten green bottles, standing on the wall,
And if x green bottles, should accidentally fall,
There'd be ten-minus-x green bottles, standing on the wall.
Ten-minus-x green bottles, standing on the wall,
Ten-minus-x green bottles, standing on the wall,
And if z green bottles, should accidentally fall,
There'd be ten-minus-open-brackets-x-plus-y-close-brackets green bottles, standing on the wall.
Ten-minus-open-brackets-x-plus-y-close-brackets green bottles, standing on the wall,
Ten-minus-open-brackets-x-plus-y-close-brackets green bottles, standing on the wall,
And if you wish to find the combined circumferences of those bottles, standing on the wall,
It's ten-minus-open-brackets-x-plus-y-close-brackets-multiplied-by-two-pi-times-the-radius-in-cm-squared circular tops of green bottles, standing on the wall.
Ten-minus-open-brackets-x-plus-y-close-brackets-multiplied-by-two-pi-times-the-radius-in-cm-squared circular tops of green bottles standing on the wall.
Ten-minus-open-brackets-x-plus-y-close-brackets-multiplied-by-two-pi-times-the-radius-in-cm-squared circular tops of green bottles standing on the wall.
And if you want to differentiate the combine circumfrences of those bottles with respect to the radius of said bottles.
You get Ten-minus-open-breacket-x-plus-y-close-bracket-times-two-pi-whoops, the bottles got lost in the differentiation.
Ten-minus-open-bracket-x-plus-y-close-bracket-times-two-pi green bottles standing on the wall
Ten-minus-open-bracket-x-plus-y-close-bracket-times-two-pi green bottles standing on the wall
If you want the reflexive property of said equation
You get Ten-minus-open-bracket-x-plus-y-close-bracket-times-two-pi equals Ten-minus-open-bracket-x-plus-y-close-bracket-times-two-pi green bottles on the wall.
Please continue!